Rigid Pavement Design

Compute the radius of relative stiffness from the slab and subgrade properties, then check Westergaard load stresses for interior, edge and corner loading combined with the warping (temperature) stresses.

Key formulas & points

Skim these first — then read the full notes below.

  • Plain cement concrete slab on granular/subgrade base
  • Corner, edge, interior loading — different critical stresses
  • IRC 58 for concrete pavement design in India

Topic details

Introduction

Rigid pavements are concrete slabs that carry traffic loads mainly by their own flexural strength, spreading the load over a wide area and transmitting only low pressure to the subgrade. IRC 58 governs their design in India.

Scope in B.Tech and GATE syllabus

Westergaard’s analysis gives the critical flexural stresses for three load positions — interior, edge and corner — with the corner and edge cases usually most severe. The radius of relative stiffness l characterises how the slab and its subgrade (modulus of subgrade reaction k) interact.

Why this topic matters in practice

Beyond wheel-load stresses, temperature differences between the top and bottom of the slab cause warping stresses, and daily/seasonal changes cause expansion and contraction; these combine with load stresses and are managed through jointing (contraction, expansion and construction joints) with dowel and tie bars.

Key relations & formulas

Formulas (Indian textbook notation)

  • Westergaard:radiusofrelativestiffnessl=[Eh3/(12(1μ2)k)]0.25Westergaard: radius of relative stiffness l = [E h^{3}/(12(1-\mu^{2}) k)]^0.25

Formulas (Indian textbook notation)

  • LoadstressPh2forinteriorloadingLoad stress ∝ \frac{P}{h^{2}} for interior loading

Formulas (Indian textbook notation)

  • Jointspacing:45mtypical;dowelbarstransferloadJoint spacing: 4-5 m typical; dowel bars transfer load

Notation and sign conventions

Relation 1 —
Westergaard:radiusofrelativestiffnessl=[Eh3/Westergaard: radius of relative stiffness l = [E h^{3}/

Formulas (Indian textbook notation)

  • Westergaard:radiusofrelativestiffnessl=[Eh3/(12(1μ2)k)]0.25Westergaard: radius of relative stiffness l = [E h^{3}/(12(1-\mu^{2}) k)]^0.25
Write this relation with symbols exactly as in Highway Engineering — Khanna & Justo before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 2 —
LoadstressPh2forinteriorloadingLoad stress ∝ \frac{P}{h^{2}} for interior loading

Formulas (Indian textbook notation)

  • LoadstressPh2forinteriorloadingLoad stress ∝ \frac{P}{h^{2}} for interior loading
Write this relation with symbols exactly as in Highway Engineering — Khanna & Justo before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 3 —
Jointspacing:45mtypical;dowelbarstransferloadJoint spacing: 4-5 m typical; dowel bars transfer load

Formulas (Indian textbook notation)

  • Jointspacing:45mtypical;dowelbarstransferloadJoint spacing: 4-5 m typical; dowel bars transfer load
Write this relation with symbols exactly as in Highway Engineering — Khanna & Justo before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.

Fundamentals and definitions

The modulus of subgrade reaction k represents the subgrade as a bed of springs (Winkler foundation); a stiffer subgrade (higher k) reduces slab deflection and stress. The radius of relative stiffness l combines the slab stiffness Eh³ and the subgrade k, defining the zone over which a load is effectively distributed.

Governing relations in practice

Westergaard derived closed-form load stresses for interior, edge and corner loading. Interior loading (wheel well inside the slab) is least severe; edge loading is more severe because the slab is supported on one side only; corner loading produces high stresses because the corner is supported on two edges and can crack diagonally.

Design and analysis considerations

Warping stress arises when a temperature gradient makes the slab try to curl, but its self-weight and subgrade restrain it, inducing flexural stress. The top is hotter by day (curling down restrained, tension at bottom) and cooler by night (reverse), so the critical combination of load plus warping is checked for both conditions.

Advanced theory and extensions

Joints control cracking from contraction and expansion; dowel bars across transverse joints transfer wheel load between slabs while allowing longitudinal movement, and tie bars across longitudinal joints hold lanes together.

Assumptions and validity limits

State assumptions explicitly before using any relation for rigid pavement design — steady state, uniform properties, linear elastic material, ideal gas, incompressible flow, etc., as applicable.
Wrong assumptions invalidate the entire solution even when the formula is correct. In Highway Engineering viva and GATE descriptive questions, listing valid assumptions often earns separate marks.

Step-by-step problem approach

1. Read the question and list given data with SI units (common in Highway Engineering papers).
2. Draw a neat labelled diagram where applicable — examiners in Indian universities award diagram marks even when arithmetic slips.
3. Identify which relation from this topic applies to rigid pavement design.
4. Use equation 1:
Westergaard:radiusofrelativestiffnessl=[Eh3/Westergaard: radius of relative stiffness l = [E h^{3}/
.
5. Use equation 2:
LoadstressPh2forinteriorloadingLoad stress ∝ \frac{P}{h^{2}} for interior loading
.
6. Substitute values, compute, and verify units and sign (direction).
7. State conclusion in one line — e.g. safe/unsafe, stable/unstable, feasible/infeasible.

Applications & exam relevance

Rigid Pavement Design appears in NHAI and state road projects. In Indian civil curricula this topic is tested because it connects theory to geometric design and pavements.
GATE and semester exams often combine rigid pavement design with earlier units — revise prerequisites before attempting mixed problems.
Industry interview panels sometimes ask: "Where did you use rigid pavement design?" — answer with a lab, mini-project, or plant visit example if possible.

Common mistakes in exams

• Treating rigid pavement like flexible pavement and using CBR-based thickness.
• Checking only interior stress and missing the more critical edge/corner stresses.
• Ignoring warping (temperature) stress, which combines with load stress.
• Confusing dowel bars (load transfer, free movement) with tie bars (hold lanes, restrain movement).

Quick revision checklist

Before attempting rigid pavement design problems, confirm you can:
1. Plain cement concrete slab on granular/subgrade base
2. Corner, edge, interior loading — different critical stresses
3. IRC 58 for concrete pavement design in India
Revise the solved examples in Highway Engineering — Khanna & Justo and one previous-year GATE or university paper for this unit.

Worked examples

Try the problem first — open the solution when you are ready to check.

Radius of relative stiffness

Problem

A concrete pavement slab has thickness h = 250 mm, E = 30 000 MPa, μ = 0.15 and rests on a subgrade with k = 80 MPa/m (0.08 N/mm³). Compute the radius of relative stiffness l.

Solution

l = [E h³/(12(1 − μ²) k)]^0.25 = [30 000 × 250³ /(12 × (1 − 0.15²) × 0.08)]^0.25. Numerator = 30 000 × 1.5625 × 10⁷ = 4.6875 × 10¹¹. Denominator = 12 × 0.9775 × 0.08 = 0.938. Ratio = 4.997 × 10¹¹, and l = (4.997 × 10¹¹)^0.25 ≈ 840 mm. This length scale is used in the Westergaard edge and corner stress equations.

Conceptual check — Rigid Pavement Design

Problem

In a Highway Engineering semester or GATE paper you are asked: "State the main assumption, the governing relation, and one practical consequence of rigid pavement design." What should a complete answer include?

Exams & GATE

Khanna & Justo — distinguish flexible vs rigid failure modes.

📖 Standard books (India)

  • Highway EngineeringKhanna & Justo

    Read: Syllabus unit

    Geometric design and pavement engineering