Qwestrum Engineering360 · Electrical & Electronics · Electrical Machines – II
Special Electrical Machines
Special machines — stepper, BLDC, switched-reluctance, universal and servo motors — trade the simplicity of the induction motor for precise position/speed control, and are analysed through their distinctive step angle, commutation and torque relations.
Exam tip: keep SI units consistent end-to-end, write the governing relation symbolically before substituting, and sanity-check magnitude and sign.
Key formulas & points
Skim these first — then read the full notes below.
- SRM: doubly salient, no rotor winding
- Linear induction motor for traction and material handling
- Servo motors: high dynamic response with feedback
Topic details
Introduction
Stepper motors move in discrete steps of θ_s = 360/(mN_r); the number of pulses fixes the position, giving open-loop digital positioning used in printers and CNC. BLDC and PMSG use permanent magnets with electronic commutation, offering high efficiency and torque density.
Scope in B.Tech and GATE syllabus
Switched-reluctance motors have a doubly salient structure and no rotor winding or magnets, making them rugged and cheap; torque comes from the tendency of the rotor to align with the excited stator pole (minimum reluctance).
Key relations & formulas
Formulas (Indian textbook notation)
(m phases, N_r rotor teeth)
Formulas (Indian textbook notation)
Notation and sign conventions
Relation 1 —
Formulas (Indian textbook notation)
Write this relation with symbols exactly as in Electrical Machines — Nagrath & Kothari before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 2 —
(m phases, N_r rotor teeth)
Write this relation with symbols exactly as in Electrical Machines — Nagrath & Kothari before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 3 —
Formulas (Indian textbook notation)
Write this relation with symbols exactly as in Electrical Machines — Nagrath & Kothari before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Fundamentals and definitions
For a stepper, total steps per revolution = 360/θ_s, and shaft speed (rpm) = (step rate in steps/s) × 60 / (steps per revolution). Microstepping subdivides each full step for finer resolution.
Governing relations in practice
Universal motors are series-wound and develop the same torque direction on AC or DC because both field and armature current reverse together; they achieve very high speed in mixers and power tools.
Design and analysis considerations
Servo systems close a feedback loop around a BLDC or DC motor with an encoder, achieving fast, accurate response; the machine is chosen for low inertia and high peak torque.
Assumptions and validity limits
State assumptions explicitly before using any relation for special electrical machines — steady state, uniform properties, linear elastic material, ideal gas, incompressible flow, etc., as applicable.
Wrong assumptions invalidate the entire solution even when the formula is correct. In Electrical Machines II viva and GATE descriptive questions, listing valid assumptions often earns separate marks.
Step-by-step problem approach
1. Read the question and list given data with SI units (common in Electrical Machines II papers).
2. Draw a neat labelled diagram where applicable — examiners in Indian universities award diagram marks even when arithmetic slips.
3. Identify which relation from this topic applies to special electrical machines.
4. Use equation 1:
5. Use equation 2:
6. Substitute values, compute, and verify units and sign (direction).
7. State conclusion in one line — e.g. safe/unsafe, stable/unstable, feasible/infeasible.
2. Draw a neat labelled diagram where applicable — examiners in Indian universities award diagram marks even when arithmetic slips.
3. Identify which relation from this topic applies to special electrical machines.
4. Use equation 1:
.
5. Use equation 2:
.
6. Substitute values, compute, and verify units and sign (direction).
7. State conclusion in one line — e.g. safe/unsafe, stable/unstable, feasible/infeasible.
Applications & exam relevance
Special Electrical Machines appears in industrial motors and generators. In Indian electrical curricula this topic is tested because it connects theory to induction and synchronous machines.
GATE and semester exams often combine special electrical machines with earlier units — revise prerequisites before attempting mixed problems.
Industry interview panels sometimes ask: "Where did you use special electrical machines?" — answer with a lab, mini-project, or plant visit example if possible.
Common mistakes in exams
• Using electrical degrees where mechanical step angle is required
• Forgetting to divide by steps-per-revolution when converting pulse rate to rpm
• Assuming SRM needs rotor windings or magnets (it has neither)
• Thinking a universal motor reverses on AC (torque direction is preserved)
• Forgetting to divide by steps-per-revolution when converting pulse rate to rpm
• Assuming SRM needs rotor windings or magnets (it has neither)
• Thinking a universal motor reverses on AC (torque direction is preserved)
Quick revision checklist
Before attempting special electrical machines problems, confirm you can:
1. SRM: doubly salient, no rotor winding
2. Linear induction motor for traction and material handling
3. Servo motors: high dynamic response with feedback
2. Linear induction motor for traction and material handling
3. Servo motors: high dynamic response with feedback
Revise the solved examples in Electrical Machines — Nagrath & Kothari and one previous-year GATE or university paper for this unit.
Worked examples
Try the problem first — open the solution when you are ready to check.
Stepper motor speed from pulse rate
Problem
A stepper motor has a step angle of 1.8°. It is driven at 500 pulses per second. Find the steps per revolution and the shaft speed in rpm.
Solution
Steps per revolution = 360/1.8 = 200 steps.
At 500 steps/s, revolutions per second = 500/200 = 2.5 rev/s.
Speed = 2.5 × 60 = 150 rpm.
At 500 steps/s, revolutions per second = 500/200 = 2.5 rev/s.
Speed = 2.5 × 60 = 150 rpm.
Conceptual check — Special Electrical Machines
Problem
In a Electrical Machines II semester or GATE paper you are asked: "State the main assumption, the governing relation, and one practical consequence of special electrical machines." What should a complete answer include?
Exams & GATE
Nagrath & Kothari — compare stepper, BLDC, SRM applications.
📖 Standard books (India)
Electrical Machines — Nagrath & Kothari
Read: Syllabus unit
Transformers, DC machines, and induction motors
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