Properties of Pure Substances

For a pure substance the state in the wet region is fixed by pressure and dryness fraction x = m_vapour/m_total, giving h = h_f + x·h_fg and s = s_f + x·s_fg. Enthalpy h = u + Pv links to steam-table data, per P.K. Nag.

Key formulas & points

Skim these first — then read the full notes below.

  • P-v and T-s diagrams: compressed liquid, wet, superheated regions
  • Critical point: no distinction between liquid and vapour
  • Clapeyron:dhfgT=vfg=hfgT(vgvf)Clapeyron: \frac{dh_{fg}}{T} = v_{fg} = \frac{h_{fg}}{T}(v_{g} - v_{f})

Topic details

Introduction

This topic teaches students to read steam tables and Mollier charts — an indispensable skill for the entire power-cycle course. A pure substance passes through compressed liquid, saturated (wet) mixture, and superheated vapour regions, each requiring a different property source.

Scope in B.Tech and GATE syllabus

P.K. Nag emphasises the phase-change (wet) region, where temperature and pressure are not independent, so the extra property needed is the dryness fraction x. All wet-region properties are then interpolated as f + x·fg.

Why this topic matters in practice

The P–v and T–s diagrams with their saturation domes are central: identifying which region a state lies in (by comparing the given property to saturation values) decides whether to use saturation tables, interpolation, or superheated tables. This region identification is the most common exam decision.

Key relations & formulas

h=u+Pvh = u + Pv
(specific enthalpy, P.K. Nag)
Tds=dhvdPT\cdot ds = dh - v dP
(Tds relations, Gibbs equation)
x=mvap(mliq+mvap)x = \frac{m_{vap}}{(m_{liq} + m_{vap})}
(dryness fraction/quality)
h=hf+xhfgh = h_{f} + x\cdot h_{fg}
(enthalpy of wet steam)

Notation and sign conventions

Relation 1 —
h=u+Pvh = u + Pv
h=u+Pvh = u + Pv
(specific enthalpy, P.K. Nag)
Write this relation with symbols exactly as in Engineering Thermodynamics — P.K. Nag before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 2 —
Tds=dhvdPT\cdot ds = dh - v dP
Tds=dhvdPT\cdot ds = dh - v dP
(Tds relations, Gibbs equation)
Write this relation with symbols exactly as in Engineering Thermodynamics — P.K. Nag before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 3 —
x=mvap/x = m_{vap}/
x=mvap(mliq+mvap)x = \frac{m_{vap}}{(m_{liq} + m_{vap})}
(dryness fraction/quality)
Write this relation with symbols exactly as in Engineering Thermodynamics — P.K. Nag before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 4 —
h=hf+xhfgh = h_{f} + x\cdot h_{fg}
h=hf+xhfgh = h_{f} + x\cdot h_{fg}
(enthalpy of wet steam)
Write this relation with symbols exactly as in Engineering Thermodynamics — P.K. Nag before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.

Fundamentals and definitions

Enthalpy h = u + Pv combines internal energy with flow work and is the workhorse property for flow devices. In the wet region, quality x weights the saturated liquid (f) and vapour (g) values: h = h_f + x·h_fg, v = v_f + x·v_fg, s = s_f + x·s_fg.

Governing relations in practice

The saturation dome on a T–s diagram separates liquid, mixture, and vapour. At the critical point the liquid and vapour become indistinguishable; above it no phase boundary exists.

Design and analysis considerations

The Clausius-Clapeyron relation dP/dT = h_fg/(T·v_fg) links the slope of the saturation line to the latent heat, allowing latent heat to be estimated from P–T data.

Advanced theory and extensions

Determining a state needs two independent properties. In the wet region T and P are dependent, so quality supplies the second. Correctly locating the state (comparing, say, given entropy against s_f and s_g) tells you whether the substance is subcooled, wet with a computed x, or superheated — the crux of every steam problem.

Assumptions and validity limits

State assumptions explicitly before using any relation for properties of pure substances — steady state, uniform properties, linear elastic material, ideal gas, incompressible flow, etc., as applicable.
Wrong assumptions invalidate the entire solution even when the formula is correct. In Thermodynamics viva and GATE descriptive questions, listing valid assumptions often earns separate marks.

Step-by-step problem approach

1. Read the question and list given data with SI units (common in Thermodynamics papers).
2. Draw a neat labelled diagram where applicable — examiners in Indian universities award diagram marks even when arithmetic slips.
3. Identify which relation from this topic applies to properties of pure substances.
4. Use equation 1:
h=u+Pvh = u + Pv
.
5. Use equation 2:
Tds=dhvdPT\cdot ds = dh - v dP
.
6. Substitute values, compute, and verify units and sign (direction).
7. State conclusion in one line — e.g. safe/unsafe, stable/unstable, feasible/infeasible.

Applications & exam relevance

Properties of Pure Substances appears in engines, boilers, and refrigeration cycles. In Indian mechanical curricula this topic is tested because it connects theory to energy, heat, and work in thermal systems.
GATE and semester exams often combine properties of pure substances with earlier units — revise prerequisites before attempting mixed problems.
Industry interview panels sometimes ask: "Where did you use properties of pure substances?" — answer with a lab, mini-project, or plant visit example if possible.

Common mistakes in exams

• Assuming T and P are independent inside the wet region (they are not — quality is needed)
• Forgetting to check whether a state is wet, saturated, or superheated before choosing a table
• Interpolation errors when reading steam tables between listed pressures/temperatures
• Using x-weighted formulas for superheated vapour where x is undefined (x > 1)

Quick revision checklist

Before attempting properties of pure substances problems, confirm you can:
1. P-v and T-s diagrams: compressed liquid, wet, superheated regions
2. Critical point: no distinction between liquid and vapour
3.
Clapeyron:dhfgT=vfg=hfgT(vgvf)Clapeyron: \frac{dh_{fg}}{T} = v_{fg} = \frac{h_{fg}}{T}(v_{g} - v_{f})
Revise the solved examples in Engineering Thermodynamics — P.K. Nag and one previous-year GATE or university paper for this unit.

Worked examples

Try the problem first — open the solution when you are ready to check.

Enthalpy of wet steam

Problem

Wet steam at a pressure where h_f = 640 kJ/kg and h_fg = 2109 kJ/kg has a dryness fraction x = 0.9. Find its enthalpy.

Solution

h = h_f + x·h_fg = 640 + 0.9 × 2109 = 640 + 1898.1 = 2538.1 kJ/kg.

Conceptual check — Properties of Pure Substances

Problem

In a Thermodynamics semester or GATE paper you are asked: "State the main assumption, the governing relation, and one practical consequence of properties of pure substances." What should a complete answer include?

Practice questions

Most-asked interview and GATE questions for this topic — expand any item for a model answer.

  1. 1
    What is Properties of Pure Substances, and why does it appear in B.Tech / GATE syllabi?

    Model answer

    For a pure substance the state in the wet region is fixed by pressure and dryness fraction x = m_vapour/m_total, giving h = h_f + x·h_fg and s = s_f + x·s_fg. Enthalpy h = u + Pv links to steam-table data, per P.K. Nag.
  2. 2
    State the relation h = u + Pv and name each symbol.

    Model answer

    The governing relation is h=u+Pvh = u + Pv. Write every symbol with SI units before substituting numbers.
  3. 3
    State the relation T·ds = dh − v dP and name each symbol.

    Model answer

    The governing relation is Tds=dhvdPT\cdot ds = dh - v dP. Write every symbol with SI units before substituting numbers.
  4. 4
    State the relation x = m_vap/ and name each symbol.

    Model answer

    The governing relation is x=mvap/x = m_{vap}/. Write every symbol with SI units before substituting numbers.
  5. 5
    State the relation h = h_f + x·h_fg and name each symbol.

    Model answer

    The governing relation is h=hf+xhfgh = h_{f} + x\cdot h_{fg}. Write every symbol with SI units before substituting numbers.
  6. 6
    Explain: P-v and T-s diagrams: compressed liquid, wet, superheated regions

    Model answer

    P-v and T-s diagrams: compressed liquid, wet, superheated regions — state the assumption range and one exam trap linked to this point.
  7. 7
    Explain: Critical point: no distinction between liquid and vapour

    Model answer

    Critical point: no distinction between liquid and vapour — state the assumption range and one exam trap linked to this point.
  8. 8
    Explain: Clapeyron: dh_fg/T = v_fg = h_fg/T(v_g − v_f)

    Model answer

    Clapeyron:dhfgT=vfg=hfgT(vgvf)Clapeyron: \frac{dh_{fg}}{T} = v_{fg} = \frac{h_{fg}}{T}(v_{g} - v_{f}) — state the assumption range and one exam trap linked to this point.
  9. 9
    How would you correct this error in a viva: Assuming T and P are independent inside the wet region (they are not — quality is needed)?

    Model answer

    Identify the wrong assumption or unit mix-up, rewrite the correct relation, and recompute with a one-line sanity check.
  10. 10
    How would you correct this error in a viva: Forgetting to check whether a state is wet, saturated, or superheated before choosing a table?

    Model answer

    Identify the wrong assumption or unit mix-up, rewrite the correct relation, and recompute with a one-line sanity check.
  11. 11
    How would you correct this error in a viva: Interpolation errors when reading steam tables between listed pressures/temperatures?

    Model answer

    Identify the wrong assumption or unit mix-up, rewrite the correct relation, and recompute with a one-line sanity check.
  12. 12
    How would you correct this error in a viva: Using x-weighted formulas for superheated vapour where x is undefined (x > 1)?

    Model answer

    Identify the wrong assumption or unit mix-up, rewrite the correct relation, and recompute with a one-line sanity check.

Exams & GATE

  • 1
    Steam tables: interpolate h, s, v using quality x for wet region.
  • 2
    Avoid: Assuming T and P are independent inside the wet region (they are not — quality is needed)
  • 3
    Avoid: Forgetting to check whether a state is wet, saturated, or superheated before choosing a table
  • 4
    Avoid: Interpolation errors when reading steam tables between listed pressures/temperatures

📖 Standard books (India)

  • Engineering ThermodynamicsP.K. Nag

    Read: Syllabus unit

    The standard thermodynamics text in most Indian universities