Qwestrum Engineering360 · Electrical & Electronics · Measurements & Instrumentation
Bridges and Potentiometers
Bridge circuits measure an unknown impedance by balancing it against known standards so the detector reads null; the balance condition then gives the unknown independent of supply variations.
Exam tip: keep SI units consistent end-to-end, write the governing relation symbolically before substituting, and sanity-check magnitude and sign.
Key formulas & points
Skim these first — then read the full notes below.
- AC bridges for L and C measurement (Hay, Owen, Schering)
- Potentiometer: null method — no current drawn at balance
- Guard terminals reduce leakage errors in high-R measurement
Topic details
Introduction
The Wheatstone bridge measures resistance: at balance no current flows through the detector and R₁/R₂ = R₃/R₄, so the unknown follows directly. Because balance is a null, the result is independent of the supply voltage.
Scope in B.Tech and GATE syllabus
AC bridges extend this to inductance and capacitance. The Maxwell bridge measures inductance using a capacitance standard; the Schering bridge measures capacitance and dielectric loss; the Hay bridge suits high-Q inductors.
Key relations & formulas
Formulas (Indian textbook notation)
Formulas (Indian textbook notation)
Formulas (Indian textbook notation)
Notation and sign conventions
Relation 1 —
Formulas (Indian textbook notation)
Write this relation with symbols exactly as in A Course in Electrical & Electronic Measurements — AK Sawhney before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 2 —
Formulas (Indian textbook notation)
Write this relation with symbols exactly as in A Course in Electrical & Electronic Measurements — AK Sawhney before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Relation 3 —
Formulas (Indian textbook notation)
Write this relation with symbols exactly as in A Course in Electrical & Electronic Measurements — AK Sawhney before substituting numbers. Examiners award partial marks for a correct setup even when arithmetic slips.
Fundamentals and definitions
At AC-bridge balance both the magnitude and phase must match, giving two equations — one for the real part (resistance) and one for the imaginary part (reactance). Solving them yields both the unknown reactive element and its associated loss resistance.
Governing relations in practice
The Kelvin double bridge eliminates lead and contact resistance errors when measuring very low resistances by adding a second ratio arm.
Design and analysis considerations
A potentiometer measures EMF by a null method: the unknown is balanced against a calibrated voltage drop with no current drawn at balance, so the source’s internal resistance causes no error — ideal for standard-cell calibration.
Assumptions and validity limits
State assumptions explicitly before using any relation for bridges and potentiometers — steady state, uniform properties, linear elastic material, ideal gas, incompressible flow, etc., as applicable.
Wrong assumptions invalidate the entire solution even when the formula is correct. In Instrumentation viva and GATE descriptive questions, listing valid assumptions often earns separate marks.
Step-by-step problem approach
1. Read the question and list given data with SI units (common in Instrumentation papers).
2. Draw a neat labelled diagram where applicable — examiners in Indian universities award diagram marks even when arithmetic slips.
3. Identify which relation from this topic applies to bridges and potentiometers.
4. Use equation 1:
5. Use equation 2:
6. Substitute values, compute, and verify units and sign (direction).
7. State conclusion in one line — e.g. safe/unsafe, stable/unstable, feasible/infeasible.
2. Draw a neat labelled diagram where applicable — examiners in Indian universities award diagram marks even when arithmetic slips.
3. Identify which relation from this topic applies to bridges and potentiometers.
4. Use equation 1:
.
5. Use equation 2:
.
6. Substitute values, compute, and verify units and sign (direction).
7. State conclusion in one line — e.g. safe/unsafe, stable/unstable, feasible/infeasible.
Applications & exam relevance
Bridges and Potentiometers appears in process control and labs. In Indian electrical curricula this topic is tested because it connects theory to measurement and transducers.
GATE and semester exams often combine bridges and potentiometers with earlier units — revise prerequisites before attempting mixed problems.
Industry interview panels sometimes ask: "Where did you use bridges and potentiometers?" — answer with a lab, mini-project, or plant visit example if possible.
Common mistakes in exams
• Writing the Wheatstone ratio the wrong way round (R₁/R₂ = R₃/R₄)
• Balancing only magnitude in an AC bridge (both real and imaginary parts must balance)
• Using a simple Wheatstone bridge for very low resistances (lead resistance dominates — use Kelvin)
• Forgetting the potentiometer draws no current at balance (why it is accurate)
• Balancing only magnitude in an AC bridge (both real and imaginary parts must balance)
• Using a simple Wheatstone bridge for very low resistances (lead resistance dominates — use Kelvin)
• Forgetting the potentiometer draws no current at balance (why it is accurate)
Quick revision checklist
Before attempting bridges and potentiometers problems, confirm you can:
1. AC bridges for L and C measurement (Hay, Owen, Schering)
2. Potentiometer: null method — no current drawn at balance
3. Guard terminals reduce leakage errors in high-R measurement
2. Potentiometer: null method — no current drawn at balance
3. Guard terminals reduce leakage errors in high-R measurement
Revise the solved examples in A Course in Electrical & Electronic Measurements — AK Sawhney and one previous-year GATE or university paper for this unit.
Worked examples
Try the problem first — open the solution when you are ready to check.
Unknown resistance in a Wheatstone bridge
Problem
A Wheatstone bridge balances with R₁ = 100 Ω, R₂ = 1000 Ω, R₃ = 200 Ω. Find the unknown R₄.
Solution
At balance R₁/R₂ = R₃/R₄ → R₄ = R₂ R₃/R₁.
R₄ = (1000 × 200)/100.
R₄ = 200000/100 = 2000 Ω = 2 kΩ.
R₄ = (1000 × 200)/100.
R₄ = 200000/100 = 2000 Ω = 2 kΩ.
Conceptual check — Bridges and Potentiometers
Problem
In a Instrumentation semester or GATE paper you are asked: "State the main assumption, the governing relation, and one practical consequence of bridges and potentiometers." What should a complete answer include?
Exams & GATE
AK Sawhney — derive balance condition for given bridge.
📖 Standard books (India)
A Course in Electrical & Electronic Measurements — AK Sawhney
Read: Syllabus unit
Bridges, transducers, and instruments
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